Free VMware 2V0-32.24 Actual Exam Questions - Question 8 Discussion
(Choose three.)
This one’s tricky but I’m going with A, D, and F. Agent type makes sense, IP is obvious, and agent status feels like a practical filter to quickly spot online or offline agents when grouping. Hostname seems less likely as a filter option for grouping since it’s more about identification than filtering. Version and protocol don’t seem like typical filters either. So for me, A, D, and F fit best here.
It’s A, D, and E for sure. Agent type, IP address, and hostname are straightforward filters to organize agents. Agent version and protocol don’t really fit as group filters in my experience.
A, D, E—version and protocol don't sound like standard filters here.
A/D/F? Agent status seems like a useful filter along with type and IP.
B imo. Agent type (A) and hostname (E) definitely make sense since you want to group agents logically. IP address (D) seems practical too for network-based filtering. I’m pretty sure agent version (B) isn’t a filter when adding agents, more for compatibility checks later. Logging protocol (C) feels off because that’s more about communication settings, not grouping. Agent status (F) is useful info but probably not a filter option here. So A, D, and E should be the three filters you can use.
I think the right answers are A, D, and E. You can filter by agent type, IP address, and hostname when adding agents to a group. Not sure if version or status are used as filters here.